综合练习-迷你DVD管理器
题目要求：
为某音像店开发一个迷你DVD管理器，实现DVD碟片的管理，包括如下功能： 新增DVD 查看DVD 删除DVD 借出DVD 归还DVD 退出DVD
提示：以下是本篇文章正文内容，下面案例可供参考
一、代码部分
代码如下（示例）：
import java.util.Scanner;
public class DVDMgr {
String[] name = new String[7]; //存储DVD名称
String[] state = new String[7]; //存储DVD借出状态：0已借出/1可借
int[] date = new int[7]; //存储DVD借出日期
int[] count = new int[7]; //存储DVD借出次数
int num = 0; //DVD数量
public void operatorDVD(int n) {
Scanner input = new Scanner(System.in);
switch (n) {
case 1:
System.out.println("添加的DVD不能超过6张");
System.out.println("----->新增DVD");
System.out.println();
String y = "y";
do {
if (num< 6) {
System.out.println("请输入新增DVD的名称：");
String name = input.next();
System.out.println("请输入新增DVD的借出状态(0已借出/1可借)：");
int state = input.nextInt();
System.out.println("请输入新增DVD的借出日期：");
int date = input.nextInt();
System.out.println("请输入新增DVD的借出次数：");
int count = input.nextInt();
for (int i = num; i < num + 1; ) {
this.name[i] = name;
if (state == 0) {
this.state[i] = "已借出";
} else if (state == 1) {
this.state[i] = "可借";
} else {
this.state[i] = "借出状态异常";
}
this.date[i] = date;
this.count[i] = count;
System.out.println("新增<<"+name+">>成功");
System.out.println("是否继续添加DVD(y/n):");
y = input.next();
num++;
break;
}
} else {
System.out.println("增加的的DVD数量超出最大添加数量6！！！");
break;
}
} while (y.equals("y"));
break;
case 2:
System.out.println("----->查看DVD");
System.out.println();
System.out.println("序号\t\t" + "DVD名称\t\t" + "DVD借出状态\t\t" + "DVD借出日期\t\t" + "DVD借出次数");
for (int i = 0; i < num; i++) {
System.out.println(i + 1 + "\t" + " " + "<<" + name[i] + ">>" + "\t" + "\t" + " " + state[i] + "\t" + "\t" + "\t" + "\t" + date[i] + "日" + "\t" + "\t" + "\t" + count[i] + "次");
}
break;
case 3:
System.out.println("----->删除DVD");
System.out.println();
System.out.println("请输入要删除的DVD序号：");
int id1 = input.nextInt();
if (id1 > num) {
System.out.println("没有这本书！！！");
return;
}
else if (state[id1 - 1].equals("已借出")) {
System.out.println("第" + id1 + "本书为借出状态，不可删除！！！");
return;
}
for (int j = id1 - 1; j < num; j++) {
if (j == num - 1) {
name[j] = null;
state[j] = "";
date[j] = 0;
count[j] = 0;
num--;
} else {
name[j] = name[j + 1];
state[j] = state[j + 1];
date[j] = date[j + 1];
count[j] = count[j + 1];
}
}
System.out.println("成功删除第" + id1 + "本书:");
break;
case 4:
System.out.println("----->借出DVD");
System.out.println();
System.out.println("请输入要借出的书本编号：");
int id2 = input.nextInt();
if (id2 > num) {
System.out.println("没有这本书！！！");
return;
}
else if (state[id2 - 1] == "已借出") {
System.out.println("该书已经被借出");
} else {
System.out.println("请输入借出日期：");
int counts = input.nextInt();
state[id2 - 1] = "已借出";
date[id2 - 1] = counts;
count[id2 - 1]++;
System.out.println("成功借出第" + id2 + "本书"+"<<"+name[id2-1]+">>");
}
break;
case 5:
System.out.println("----->归还DVD");
System.out.println();
System.out.println("请输入要归还的书本编号：");
int id3 = input.nextInt();
if (id3 > num) {
System.out.println("没有这本书！！！");
return;
}
else if (state[id3 - 1] == "可借") {
System.out.println("该书还未被借出");
} else {
System.out.println("借书日期为："+date[id3 - 1]+"日");
System.out.println("应付租金：" + date[id3 - 1] * 3);
state[id3 - 1] = "可借";
date[id3 - 1] = 0;
System.out.println("成功归还第" + id3 + "本书"+"<<"+name[id3-1]+">>");
}
break;
case 6:
System.out.println("退出成功！！！");
System.exit(0);
default:
System.out.println("输入的功能序号有误，请重新输入！");
}
}
public static void main(String[] args) {
int a = 0;
DVDMgr dvd = new DVDMgr();
do {
System.out.println("欢迎使用迷你DVD管理器");
System.out.println("---------------------------------------------------");
System.out.println("1. 新增DVD");
System.out.println("2. 查看DVD");
System.out.println("3. 删除DVD");
System.out.println("4. 借出DVD");
System.out.println("5. 归还DVD");
System.out.println("6. 退出DVD");
System.out.println("---------------------------------------------------");
System.out.print("请选择：");
Scanner input = new Scanner(System.in);
int n = input.nextInt();
dvd.operatorDVD(n);
System.out.print("请输入0返回：");
a = input.nextInt();
} while (a == 0);
}
}
二、运行截图：
